Homework Help: chemistry

Posted by Zarion Gibbs on Wednesday, May 4, 2011 at 9:14am.

A 10.0-mL sample of vinegar, which is an aqueous solution of acetic acid, CH3COOH, requires 16.5 XML of a 0.500M NaOH solution to reach the endpoint in a titration (where the moles of acid are equal to the moles of base). What is the molarity of the acetic acid solution

chemistry - DrBob222, Wednesday, May 4, 2011 at 6:00pm
How many moles NaOH do you have? That is M x L = ??
How many moles acetic acid do you have? That will be the same thing; the problem tells you.
Concn acetic acid = moles/L soln. The problem gives you 10 mL which is 0.010 L so M = ??moles/0.010L = ??

Answer this Question

Related Questions

Chem - Please tell me if these are right! 1.How many milliliters of 0.215 M NaOH...
Chemistry - A 10.0 ml sample of vinegar which is an aqueous solution of acetic ...
Chemistry - If a 11.0 mL sample of vinegar (aqueous acetic acid ) requires 19.0 ...
chem. - A 10.0 mL of vinegar, an aqueous solution of acetic acid (HC2H3O2), is ...
Chemistry - Commercial vinegar was titrated with NaOH solution to determine the ...
chemistry - You were given 25.00 ml of an acetic acid solution of unknown ...
chem-acid-base titrations - Acetic acid (HC2H3O2) is an important component of ...
Chemistry - A sample of 25.00 mL of vinegar is titrated with a standard 1.02 M ...
Chemistry - Thanks for your help; I am still have a few problems, could you ...
Chemistry - Vinegar is a dilute solution of acetic acid. What is the ...

For Further Reading

First Name:
School Subject:
Answer: