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Q1) Find area of the triangle ABC where AB=c, AC=b and BC=a. When a=b=c=12m

  • maths - ,

    see your next post

  • maths - ,

    Area of tiangle = 1/2 base*altitude
    = 1/2 *12*12

  • maths - ,

    Area of tiangle = 1/2 base*altitude
    = 1/2 *12*12
    = 72sq. unit

  • maths - ,

    1. Label all the sides as a, b and c. Where A is 15m, B is 10m & C is 12m (as these are corresponding to their sides.
    2. Write down the formula for the cosine rule (because were looking for the angle, CosA will be the subject rather than a^2):
    CosA=b^2+c^2-a^2/2bc
    2.Substitute your values:
    CosA=10^2+12^2-15^2/2*10*12
    4. Now, because you will be looking for the angle, you need to enter SHIFT + Cos on your calculator in order for it find the angle.
    5. Your final answer should be 85.5 degrees (Rounded to 1 d.p.)

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