Posted by **jenny** on Wednesday, May 4, 2011 at 6:46am.

Q1) Find area of the triangle ABC where AB=c, AC=b and BC=a. When a=b=c=12m

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**Reiny**, Wednesday, May 4, 2011 at 7:04am
see your next post

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**dharmendra**, Monday, March 12, 2012 at 4:44am
Area of tiangle = 1/2 base*altitude

= 1/2 *12*12

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**dharmendra**, Monday, March 12, 2012 at 4:45am
Area of tiangle = 1/2 base*altitude

= 1/2 *12*12

= 72sq. unit

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**Jenny B. Francis**, Thursday, October 15, 2015 at 4:38pm
1. Label all the sides as a, b and c. Where A is 15m, B is 10m & C is 12m (as these are corresponding to their sides.

2. Write down the formula for the cosine rule (because were looking for the angle, CosA will be the subject rather than a^2):

CosA=b^2+c^2-a^2/2bc

2.Substitute your values:

CosA=10^2+12^2-15^2/2*10*12

4. Now, because you will be looking for the angle, you need to enter SHIFT + Cos on your calculator in order for it find the angle.

5. Your final answer should be 85.5 degrees (Rounded to 1 d.p.)

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