March 24, 2017

Post a New Question

Posted by on Tuesday, May 3, 2011 at 11:01pm.

If the voltage of the cell is -0.1288V at 25Celsius when [Pb2+]=0.1403M and the pressure of H2=1atm, what is the pH
Pb(s)+2H+(aq)<-> Pb2+(aq) +H2(g) E0 = 0.1260V

  • College Chemistry - , Tuesday, May 3, 2011 at 11:35pm

    Ecell = Eocell - (0.05916/2)log(Pb^2+)*PH2/(H^+)^2
    Substitute and solve for H^+, then convert to pH.

  • College Chemistry - , Thursday, May 5, 2011 at 9:23pm

    Thank you DrBob222

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question