Posted by mary on Tuesday, May 3, 2011 at 3:35pm.
f(x) = ln(e^x - e^-x)
f'(x) = (e^x + e^-x)/(e^x - e^-x)
f''(x) = [(e^x - e^-x)(e^x - e^-x) - (e^x + e^-x)(e^x + e^-x)]/(e^x - e^-x)^2
= [(e^x - e^-x)^2 - (e^x + e^-x)^2]/(e^x - e^-x)^2
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