Posted by please help me on Tuesday, May 3, 2011 at 10:18am.
The volume of the room is
7.47x14.9x2.87 = 319.4 m^3
= 319.4*10^6 liters.
If you assume the number of moles in the room remains the same, you are talking about a constant-volume heating. The specific heat for that, for a diatomic molecule, is (5/2)*R = 4.967 cal/mole C
The number of liters per mole at 19.9 C and 101 kPa (1 atm) is
22.4*(293.1/273.3) = 24.0 l/mol
Number of moles = 319.4*10^6 l/24.0 l/mol = 13.3*10^6 mol
heat required to raise temperature 1.8 C
= 1.8 C*4.967 cal/mole C*13.3*10^6 mole = ___
The volume of the room is
7.47x14.9x2.87 = 319.4 m^3
= 319.4*10^3 liters.
not 319.4*10^6 liters.
The volume of the room is
7.47x14.9x2.87 = 319.4 m^3
= 319.4*10^3 liters.
not 319.4*10^6 liters.
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