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posted by kozy on Tuesday, May 3, 2011 at 12:01am.
Given the quadratic function f(x) = 16x^2 – 64x + 64, find a value of x such that f(x) = 16.
16 = 16x^2 - 64x + 64 0 = 16x^2 - 64x + 64 - 16 (using quadratic formula) x= 3 or x =1
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