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January 29, 2015

January 29, 2015

Posted by **Joe** on Tuesday, May 3, 2011 at 12:00am.

I can compute airspeed and actual direction using law of sines and cosines but not sure how to figure out the requested 72 degree part.

- PreCalc - Vectors -
**Henry**, Wednesday, May 4, 2011 at 7:12pmX = hor. = 660 + 35cos345 = km/h.

Y = ver. = 35sin345 =

tanA = Y/X = -9.06 / 693.8 = -.0131,

A = -0.75 deg.

A + B = 72,

-0.75 + B = 72,

B = 72 + 0.75 = 72.75 deg. = Direction.

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