Homework Help: PreCalc - Vectors

Posted by Joe on Tuesday, May 3, 2011 at 12:00am.

An airplane is flying with an airspeed of 660 Kilometers per hour. The wind is blowing from 345 degrees at 35 km/h. What direction should the airplane take so that, with the wind, the plane will be flying in a direction of 72 degrees?

I can compute airspeed and actual direction using law of sines and cosines but not sure how to figure out the requested 72 degree part.

PreCalc - Vectors - Henry, Wednesday, May 4, 2011 at 7:12pm
X = hor. = 660 + 35cos345 = km/h.

Y = ver. = 35sin345 =

tanA = Y/X = -9.06 / 693.8 = -.0131,
A = -0.75 deg.

A + B = 72,
-0.75 + B = 72,
B = 72 + 0.75 = 72.75 deg. = Direction.

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