The reaction 2 H2S(g)--> 2 H2(g) + S2(g) has Kp = 2.4 x 10-4 at 1073 K. A reaction mixture contains 0.146 atm of H2, 0.041 atm of S2 and 0.574 atm of H2S. What is the value of Qp?
To find the value of Qp, we need to calculate the partial pressures of H2, S2, and H2S using the given concentrations of each gas.
The balanced equation for the reaction is:
2 H2S(g) --> 2 H2(g) + S2(g)
According to the equation, the stoichiometric ratio of H2S, H2, and S2 is 2:2:1.
Given concentrations:
[H2] = 0.146 atm
[S2] = 0.041 atm
[H2S] = 0.574 atm
Using the stoichiometry, we can calculate the corresponding partial pressures of each gas:
Partial pressure of H2 = 2 * [H2] = 2 * 0.146 atm = 0.292 atm
Partial pressure of S2 = 1 * [S2] = 1 * 0.041 atm = 0.041 atm
Partial pressure of H2S = 2 * [H2S] = 2 * 0.574 atm = 1.148 atm
Now we can calculate the value of Qp by substituting the partial pressures into the expression for Qp:
Qp = (P_H2)^2 * (P_S2) / (P_H2S)^2
Qp = (0.292)^2 * (0.041) / (1.148)^2
Calculating this expression will give us the value of Qp.