Posted by Eric on Monday, May 2, 2011 at 10:53pm.
assuming the gas is ideal, we can use Charles' Law:
V1/T1 = V2/T2
where
V1 = initial volume
V2 = final volume
T1 = initial temperature (in Kelvin)
T2 = final temperature (in Kelvin)
we first convert the given temp to Kelvin:
T1 = 30 + 273.15 = 303.15 K
substituting,
V1/T1 = V2/T2
0.9 / 303.15 = 1.2 / (T2)
T2 = 1.2*303.15/0.9
T2 = 404.2 K or 131.05 deg C
hope this helps~ :)
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