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Chem3

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A solution is prepared by dissolving 22.8 mL of methanol (d = 0.782 g/mL) in 100 mL of water (d = 1.00 g/mL) so that the final volume of solution is 118 mL. What is the percent methanol by mass?

  • Chem3 - ,

    22.8 mL methanol x 0.782 g/mL = grams methanol.
    mass soln = mass methanol + mass H2O
    %methanol w/w = (mass methanol/total mass soln)*100 = ??

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