Homework Help: Chem3

Posted by Ryan on Monday, May 2, 2011 at 10:12pm.

A solution is prepared by dissolving 22.8 mL of methanol (d = 0.782 g/mL) in 100 mL of water (d = 1.00 g/mL) so that the final volume of solution is 118 mL. What is the percent methanol by mass?

Chem3 - DrBob222, Monday, May 2, 2011 at 10:40pm
22.8 mL methanol x 0.782 g/mL = grams methanol.
mass soln = mass methanol + mass H2O
%methanol w/w = (mass methanol/total mass soln)*100 = ??

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