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April 18, 2015

April 18, 2015

Posted by **katy** on Monday, May 2, 2011 at 10:10pm.

- physics -
**Jai**, Monday, May 2, 2011 at 11:04pmassuming the air is ideal, we can use the formula,

P1/T1 = P2/T2

where

P1 = initial pressure

P2 = final pressure

T1 = initial temperature (in Kelvin)

T2 = final temperature (in Kelvin)

we first convert the given temp to Kelvin:

T1 = 20 + 273.15 = 293.15 K

T2 = 250 + 273.15 = 523.15 K

substituting,

P1/T1 = P2/T2

1/293.15 = (P2)/523.15

P2 = 523.15/293.15

P2 = 1.79 atm

hope this helps~ :)

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