Posted by sam on Monday, May 2, 2011 at 10:09pm.
(Area)*(Thermal conductivity)*(temperature difference)*(time)/(thickness) = __ J
Make sure you use meters and square meters for thickness and area, respectively. Time must be 60 s
Area=o.oo2m temperature difference=150oK thermal conductivity=0.84Js-1m-1K-1 thickness=0.03m time=60s ^=delta thermal conductivity=K A^T t\L 0.84*0.03*150*60\0.002=113400J
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