Posted by **carol** on Monday, May 2, 2011 at 8:09pm.

Given the quadratic function f(x) = x2 – 18x + 81, find a value of x such that f(x) = 16.

- math -
**Mgraph**, Monday, May 2, 2011 at 8:22pm
Solve the equation

x^2-18x+81=16

x^2-18x+65=0

- math -
**Jai**, Monday, May 2, 2011 at 8:29pm
f(x) = x^2 – 18x + 81

f(x) = 16

substituting the value of f(x) to the quadratic equation,

16 = x^2 - 18x + 81

0 = x^2 - 18x + 81 - 16

0 = x^2 - 18x + 65

0 = (x-13)(x-5)

thus,

x = 13 and x = 5

hope this helps~ :)

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