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April 20, 2014

April 20, 2014

Posted by **Pate** on Monday, May 2, 2011 at 7:55pm.

Back to the subject I'm really confused with acceleration calculation and velocity, time, speed, distance, etc.

I have a quiz on it tommorow and a test on thursday, so if anyone could help that would be fantastic! Oh and I also have this really hard worksheet that is getting graded and I certinly will FAILLLLL! :(

- Physical Science -
**drwls**, Monday, May 2, 2011 at 9:12pmYou have not asked a question. That is probabkly why no one has responded thus far. If you wish, send us a few specific questions from your worksheet that are giving you trouble.

Velocity is the rate of change of location and accleration is the rate of change of velocity.

Time is what it is.

- Physical Science -
**Jai**, Monday, May 2, 2011 at 9:28pmi'll try my best to explain them as simple as possible.

(i) distance - how far an object has moved. it is in units of length (meters, kilometers, etc)

(ii) speed - distance traveled over certain time, or in formula,

v = d/t

where

v = speed

d = distance

t = time

it has units of length/time. for example m/s, km/h, etc.

(iii) velocity - displacement over time. it is almost the same with speed except that speed is scalar (or does NOT indicate the direction), while velocity is vector (or it indicates the direction).

(iv) acceleration - change in velocity over time, or in formula,

a = (v2 - v1)/t

where

a = acceleration

v2 = final velocity

v1 = initial velocity

t = time elapsed

it has the units of length/time^2. for example, m/s^2.note that if in the problem it is stated that the velocity is constant, acceleration is zero.

note that the formula to use to calculate these quantities still depend on the problem. some of the formulas here are for objects in 'Uniform Motion' (a = 0, thus v = constant) and can not be used for objects in 'Uniformly Accelerated Motion' (a = constant and not equal to 0)

hope this helps~ :)

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