Posted by **mariah** on Monday, May 2, 2011 at 7:47pm.

find the perimeter of the polygon with vertices A(-5,-3) B(1,0) C (3,-4) D(-3,-7)

- geometry -
**MathMate**, Monday, May 2, 2011 at 9:25pm
The distance between two given points P1(x1,y1) and P2(x2,y2) in the coordinate plane is given by the expression:

distance P1-P2 = sqrt((x2-x1)^2+(y2-y1)^2)

A(-5,-3) B(1,0) C (3,-4) D(-3,-7)

For example, the distance

AB = sqrt((1-(-5))^2+(0-(-3))^2)

= sqrt(6^2+3^2)

= sqrt(45)

= 6.708...(approx.)

Proceed the same way for BC, CD and CA and add up the four distances to get the perimeter.

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