Saturday

April 19, 2014

April 19, 2014

Posted by **Patrick** on Monday, May 2, 2011 at 7:25pm.

- algebra 1 honors -
**Angeline**, Monday, June 20, 2011 at 12:27am10

- algebra 1 honors -
**Angeline**, Monday, June 20, 2011 at 12:32amleave r on one side by subtracting 5/3 r to the left side.

r = (5/3)r + (20/3)

-(5/3)r + r = 20/3

(-2/3)r = 20/3

solving for r:

(20/3) / (-2/3) = -10

Answer: r = -10

**Related Questions**

Algebra - add. (5r^4-3r^3+3r^2+14r-8)+(r^5+8r^3+7r^2-3r+5)+(-8r^4+r^2-8r-9)the ...

algebra - if (6r - x) is on factors of 18r^2 + 12ry - 3xr - 2xy, what is the ...

algerbra - 3-3r=4 Do you wish to solve for r? Put r on one side and everything ...

algebra - 3r-5s=-14 3r+3s-56

alg - Multiply: 8r + 16 / 24r - 24 * 6r - 6 / 3r + 6 a) 2/3r b) 2/3 c) 2 d) 2(r...

Algebra 1 - 4/3r-3<r+2/3-1/3r.......... ...........HELP ME PLEASE

algebra honors - I was placed into algebra honors instead of advanced math.. I ...

AALGEBRA - NEED HELP SOLVING 3h/2 = 30 and 3(3+r)= 2r+4 so 3x3=9,3xr=3r = 2r+4 9...

Algebra 2 - Is this how you solve t(t+1)(t+2)=0, x^3+4x=4x^2, and 3r^2=4r-1? t(t...

grade nine math - is the answer to my equation right? equation: 5(3r-7)+r=3(r-3...