If r=5/3r+20/3, what is r? URGENT!!!!
10
leave r on one side by subtracting 5/3 r to the left side.
r = (5/3)r + (20/3)
-(5/3)r + r = 20/3
(-2/3)r = 20/3
solving for r:
(20/3) / (-2/3) = -10
Answer: r = -10
To find the value of r in the equation r = (5/3)r + (20/3), we need to isolate the variable r.
Step 1: Distribute the coefficient (5/3) to the term r:
r = (5/3)r + (20/3)
r = (5/3)r * 1 + (20/3)
Step 2: Combine like terms:
r - (5/3)r = (20/3)
(3r/3) - (5/3)r = (20/3)
(3r - 5r)/3 = (20/3)
Step 3: Simplify the left side by combining like terms:
(-2r/3) = (20/3)
Step 4: Multiply both sides of the equation by the reciprocal of (-2/3), which is (-3/2):
((-3/2) * (-2r/3)) = ((-3/2) * (20/3))
r = -30/6
Step 5: Simplify the right side of the equation:
r = -5
Therefore, the value of r in the equation r = (5/3)r + (20/3) is -5.