Monday

July 27, 2015

July 27, 2015

Posted by **Patrick** on Monday, May 2, 2011 at 7:25pm.

- algebra 1 honors -
**Angeline**, Monday, June 20, 2011 at 12:27am10

- algebra 1 honors -
**Angeline**, Monday, June 20, 2011 at 12:32amleave r on one side by subtracting 5/3 r to the left side.

r = (5/3)r + (20/3)

-(5/3)r + r = 20/3

(-2/3)r = 20/3

solving for r:

(20/3) / (-2/3) = -10

Answer: r = -10