Posted by **Mhy** on Monday, May 2, 2011 at 4:03pm.

A rocket carrying a weather satellite is launched. As it moves through space, the rocket is tracked by two tracking stations located 24 km. apart, beneath the rocket. The 2 tracking stations both lie west of the launching pad. at a specific moment, the rocket's angle of elevation from Station X is 40 deg. while the rocket's angle of elevation from Station Y is 70 deg. Both tracking stations are west of the rocket at this moment. At this moment, what is the altitude of the rocket, correct to one decimal place?

- trig pls.. help me -
**Reiny**, Monday, May 2, 2011 at 4:15pm
make a sketch, on a straight line mark off points

X, Y, and Z, where Z is then end of the altitude SZ, where S is the satellite.

Angle X = 40°

angle SYZ=70°

XY = 24

in triangle XYS,

angle x=40, angle XYS = 110 , and angle XSY = 30°

by the sine law:

YS/sin40 = 24/sin30

YS = 30.8538

in right-angled triangle SYZ,

RZ/30.8538 = cos 70

RZ = 10.55

the height is appr. 10.6 km

- trig pls.. help me -
**Mhy**, Monday, May 2, 2011 at 5:32pm
thank you so much...

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