Posted by Mhy on .
A rocket carrying a weather satellite is launched. As it moves through space, the rocket is tracked by two tracking stations located 24 km. apart, beneath the rocket. The 2 tracking stations both lie west of the launching pad. at a specific moment, the rocket's angle of elevation from Station X is 40 deg. while the rocket's angle of elevation from Station Y is 70 deg. Both tracking stations are west of the rocket at this moment. At this moment, what is the altitude of the rocket, correct to one decimal place?

trig pls.. help me 
Reiny,
make a sketch, on a straight line mark off points
X, Y, and Z, where Z is then end of the altitude SZ, where S is the satellite.
Angle X = 40°
angle SYZ=70°
XY = 24
in triangle XYS,
angle x=40, angle XYS = 110 , and angle XSY = 30°
by the sine law:
YS/sin40 = 24/sin30
YS = 30.8538
in rightangled triangle SYZ,
RZ/30.8538 = cos 70
RZ = 10.55
the height is appr. 10.6 km 
trig pls.. help me 
Mhy,
thank you so much...