Posted by Paul on Monday, May 2, 2011 at 3:14pm.
I can see it as being factored to
(3^x - 3^5)(3^x - 3^5) = 0
so 3^x - 3^5 = 0
3^x = 3^5
x = 5
Rewrite the given equation using the substitutions x=rcos@ and y=rsin@. (@=theta)
Simplify your answer.
(2x-3)*(x^2+9)*(x+5)=0
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