If 150 g of water is heated from 3.0 celieus to 48.0 celieus how many joules of heat are needed

To calculate the amount of heat needed to raise the temperature of a substance, you can use the heat capacity equation:

Q = mcΔT

Where:
Q = amount of heat (in joules)
m = mass of the substance (in grams)
c = specific heat capacity of the substance (in joules/gram degrees Celsius)
ΔT = change in temperature (in degrees Celsius)

For water, the specific heat capacity is approximately 4.18 joules/gram degrees Celsius.

Now, let's apply these values to the given information:

m = 150 g (mass of water)
c = 4.18 joules/gram degrees Celsius (specific heat capacity)

ΔT = 48.0°C - 3.0°C = 45.0°C (change in temperature)

Substituting these values into the equation, we can calculate the amount of heat required:

Q = (150 g) * (4.18 joules/g°C) * (45.0°C)
Q ≈ 28,215 joules

Therefore, approximately 28,215 joules of heat are needed to raise the temperature of 150 grams of water from 3.0°C to 48.0°C.