Posted by Dwayne on Monday, May 2, 2011 at 11:35am.
Then set the initial KEnergy equal to the potential energy at the surface of EArth.
1/2 mv^2= GMe*m/re
solve for escape velocity, v
v^2 = 2Mg/r + (u^2 -2Mg/d )
Is that right
Why did you make it so complicated?
1/2 m v^2=GMe m/re
v^2= 2GMe/re
take the square root of each side.
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