Posted by Dwayne on Monday, May 2, 2011 at 11:35am.
Law of Gravitation Find an expression for the magnitude of the initial velocity that a projectile must possess in order to leave the earth when air friction is neglected.
The gravitational constant for g is, G = 6.67428*10^11 m^3 Kg^1 s^2
Please answer the question fully and please give any helpful websites, thankyou.
Also I know calculus.

Math BOBPURSLEY HELP HELP HELP HELP  bobpursley, Monday, May 2, 2011 at 11:39am
Then set the initial KEnergy equal to the potential energy at the surface of EArth.
1/2 mv^2= GMe*m/re
solve for escape velocity, v

Math BOBPURSLEY HELP HELP HELP HELP  Dwayne, Monday, May 2, 2011 at 11:48am
v^2 = 2Mg/r + (u^2 2Mg/d )
Is that right

Math BOBPURSLEY HELP HELP HELP HELP  bobpursley, Monday, May 2, 2011 at 12:00pm
Why did you make it so complicated?
1/2 m v^2=GMe m/re
v^2= 2GMe/re
take the square root of each side.
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