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What is the pH of a 0.0250 M solution of HCN? Ka = 4.0x10^-10

  • Chemistry -

    HCN >< H+ CN-

    .250-x <> x+ x

    4E-10=x^2/(.250-x) appx x^2/.250

    [H+]= sqrt (4*.250E-10)

    = 1E-5

    pH= 5

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