Monday

April 21, 2014

April 21, 2014

Posted by **Crissy XD** on Monday, May 2, 2011 at 3:06am.

There are 41 pigs and chickens on a farm. If there are 100 legs counted altogehter, how many of each animal are there?

One day, 5/6 of the office staff came to work. If three more had been away, this fraction would have decreased to 3/4. How many people are on full staff?

Mrs. Grant was 20 when her eldest child, tess, was born. Carly was born 2 years later and Troy another 4 years later. Now the average of their four ages is 39. How old are Mrs. Grant and her three children?

Please help...

- Math -
**Henry**, Tuesday, May 3, 2011 at 7:03pm2. We have X pigs and Y chickens.

Eq1: X + Y = 41 Pigs and chicken.

Each pig has 4 legs and each chicken has 2 legs:

Eq2: 4X + 2Y = 100 Legs.

Multiply both sides of Eq1 by -2 and

add the 2 Eqs:

-2X - 2Y = - 82,

4X + 2Y = 100,

2X = 18,

X = 9 Pigs.

Substitute 9 for X in Eq1:

9 + y = 41,

Y = 41 - 9 = 32 Chickens.

3. 5X/6 - 3 = 3X/4,

Multiply both sids by 12:

10x - 36 = 9X,

10X - 9X = 36,

X = 36 Staff members.

4. Tess: X Years old.

Mrs. Grant: X+20.

Carly: X-2.

Troy: X-6.

(X + (X+20) + (X-2) + (X-6)) / 4 = 39,

(4X + 12) / 4 = 39,

Multiply both sides by 4:

4X + 12 = 156,

4X = 156 - 12 = 144,

X = 36 = Tess's age.

X+20 = 36+20 = 56 = Mrs. Grant's age.

X-2 = 36-2 = 34 = Carly's age.

X-6 = 36-6 = 30 = Troy's age.

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