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Posted by on Sunday, May 1, 2011 at 11:42pm.

what is the solution set (in terms of pi) of the equation sin2t-cos^2t=1=sin^2t+sint in the interval 0<t<2pi

  • trigonometry-math - , Monday, May 2, 2011 at 12:01am

    Do you really mean:
    sin(2t)-cos²(t)=1=sin²(t)+sin(t)
    Also, this is equivalent to two equations.

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