Friday
April 25, 2014

Homework Help: trigonometry-math

Posted by renee on Sunday, May 1, 2011 at 11:42pm.

what is the solution set (in terms of pi) of the equation sin2t-cos^2t=1=sin^2t+sint in the interval 0<t<2pi

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

math - Eliminate the parameter (What does that mean?) and write a rectangular ...
trig - If cos(t)=(-7/8) where pi<t<(3pi/2), find the values of the ...
Trig - sin^4t-cos^4t/sin^2t cos^2t= sec^2t-csc^2t i have =(sin^2t+cos^2t)(sin^2t...
calculus/Trig - Suppose you wish to express sin(3t) in terms of sint and cost. ...
math - Can anyone help w/ these. 1) Solve the equation in the internal [0deg, ...
math - Prove that for all real values of a, b, t (theta): (a * cos t + b * sin t...
Pre CAL!! Please HELP - find the solutions of the equation that are in the ...
Pre CAL!! Please HELP - find the solutions of the equation that are in the ...
Trig - Given: cos u = 3/5; 0 < u < pi/2 cos v = 5/13; 3pi/2 < v < ...
Math - Hi, I wanted to know how wanted to know if i was doing this step right ...

Search
Members