Posted by renee on Sunday, May 1, 2011 at 11:42pm.
what is the solution set (in terms of pi) of the equation sin2tcos^2t=1=sin^2t+sint in the interval 0<t<2pi

trigonometrymath  MathMate, Monday, May 2, 2011 at 12:01am
Do you really mean:
sin(2t)cos²(t)=1=sin²(t)+sin(t)
Also, this is equivalent to two equations.