theoretical yield of NaCl using 0.016 mols HCl with HCl + NaOH - NaCl + H2O as the equation for the reaction
Just follow the steps.
http://www.jiskha.com/science/chemistry/stoichiometry.html
To calculate the theoretical yield of NaCl in the reaction HCl + NaOH -> NaCl + H2O using 0.016 moles of HCl, we need to know the stoichiometry of the reaction. The stoichiometry of a chemical reaction describes the molar ratios of the reactants and products involved.
From the balanced chemical equation HCl + NaOH -> NaCl + H2O, we can see that the molar ratio between HCl and NaCl is 1:1. This means that for every 1 mole of HCl that reacts, 1 mole of NaCl is produced.
Therefore, if you have 0.016 moles of HCl, the theoretical yield of NaCl can be calculated as follows:
Theoretical yield of NaCl = 0.016 moles HCl * (1 mole NaCl / 1 mole HCl)
Theoretical yield of NaCl = 0.016 moles NaCl
So, the theoretical yield of NaCl using 0.016 moles of HCl is also 0.016 moles.
Note: The actual yield of a reaction may be different from the theoretical yield due to various factors such as incomplete reactions, side reactions, or experimental errors.