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Chemistry

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OF2(g) + H2O(g) -> O2(g) +2HF(g) ΔH°rxn = -318 kJ

Using bond energies, calculate the bond dissociation energy of the O-F bond, in OF2.


This is the question and I got 438 as the answer, which is wrong. I don't know what I did wrong??

  • Chemistry - ,

    If you will post your work I'll try to find the error. I found numbers in my book and you might check what you used. If I didn't skip a line, I read
    O=O = 498
    O-H = 464
    HF = 569
    Your numbers may differ since we aren't using the same text (I sure of that) but they should be close.

  • Chemistry - ,

    So I have
    O=O = 498
    O-H = 436
    HF = 565

    -318 = (x+436) - (498+565)
    Since reaction=broken-made

    -318 = x+436 - 1063

    745 = x + 436

    x= 309

    Isn't this what you are supposed to do? :(

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