solve for x
-2x^2-4x+5=0
is the answer -2.22, 0.22
I have no idea how you got your answers.
Didn't you test them by substituting them back into the equation ?
-2x^2 - 4x + 5 = 0
2x^2 + 4x - 5 = 0
x = (-4 ± √56)/4 = .8708 or -2.8708
Thank you so much could you look at my other problem
To solve the quadratic equation -2x^2-4x+5=0, you can use the quadratic formula. The quadratic formula is given by:
x = (-b ± √(b^2-4ac))/(2a)
In the equation -2x^2-4x+5=0, we have a = -2, b = -4, and c = 5. Plugging in these values into the quadratic formula, we get:
x = (-(-4) ± √((-4)^2-4(-2)(5)))/(2(-2))
x = (4 ± √(16+40))/(-4)
x = (4 ± √56)/(-4)
Simplifying further, we get:
x = (4 ± √(4*14))/(-4)
x = (4 ± 2√14)/(-4)
x = 2(1 ± √14)/(-4)
x = -(1 ± √14)/2
Therefore, the solutions for x are approximately -2.22 and 0.22, when rounded to two decimal places.