Homework Help: Chemistry

Posted by Anonymous on Sunday, May 1, 2011 at 1:50pm.

The cloth shroud from around a mummy is found to have a carbon-14 activity of 8.1 disintegrations per minute per gram of carbon as compared with living organisms that undergo 15.2 disintegrations per minute per gram of carbon.

From the half-life for carbon-14 decay, 5715 yr, calculate the age of the shroud.

Chemistry - DrBob222, Sunday, May 1, 2011 at 1:58pm
k = 0.693/t_1/2
k = 0.693/5715yr = 1.213E-4
Substitute k into the below equation.
ln(No/N) = kt
No = 15.2
N = 8.1
k from above.
Solve for t (in years).
Chemistry - Anonymous, Sunday, May 1, 2011 at 2:05pm
Thanks.

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