Sunday

August 31, 2014

August 31, 2014

Posted by **paul** on Sunday, May 1, 2011 at 1:30pm.

Find the area of the region R

- calculus -
**Reiny**, Sunday, May 1, 2011 at 2:44pmthe curve starts at (-1,0)

area = [integral] (x+1)^(1/2) dx from -1 to 3

= (2/3)(x+1)^(3/2) from -1 to 3

= (2/3)(4)^(3/2)

= 16/3

check my arithmetic

**Related Questions**

Calculus - This problem set is ridiculously hard. I know how to find the volume ...

calculus - Find the volume of the solid generated by revolving the region about ...

calculus - The figure shows the region bounded by the x-axis and the graph of . ...

Calculus - Let f be the function given by f(x)=(x^3)/4 - (x^2)/3 - x/2 + 3cosx. ...

Calculus - 1. Find the area of the region bounded by the curves and lines y=e^x ...

calculus - A region is bounded by the function y=2x^2+3 and the x-axis over the ...

CALCULUS - The region R is bounded by the x-axis, y-axis, x = 3 and y = 1/(sqrt(...

CALCULUS HELP PLZ - The region R is bounded by the x-axis, y-axis, x = 3 and y...

calculus - A region is bounded in the second quadrant by the curve y = ln(1–x), ...

calculus - let R be the region bounded by the graphs of y = sin(pie times x) and...