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September 30, 2014

September 30, 2014

Posted by **Joe** on Sunday, May 1, 2011 at 11:14am.

- Algebra -
**MathMate**, Sunday, May 1, 2011 at 12:03pmThe residue value after each year is 100-25=75% of the previous year.

So after n years, the value is

P(0.75^n)

=$17,500 * 0.75^5

=...

I'll let you do the calculations.

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