I don't fully understand factorization in algebra. I've got a problem:
9x-27x^3. Can you please help me?
First take out the obvious factors, for example, 9 divides 9 and 27, so 9 is a common factor:
9÷9=1, 27÷9=3, so
9(x-3x^3)
Now x divides x and x divides 3x^3,
again,
x÷x = 1, 3x^3÷x=3x*x*x÷x=3x^2
so
9x(1-3x^2)
If we are working with rational factorization (i.e. with factors that are integers or fractions), that is as far as we can go.
The answer is therefore
9x(1-3x^2).