Posted by Hannah on Sunday, May 1, 2011 at 10:47am.
1) evaluate
integral of xe^3x dx
2) evaluate integral form 1 to 0 of 4e^2x dx
I just need help finding the anitderivative. Would it be 2e^2x?

Math  Damon, Sunday, May 1, 2011 at 11:12am
u = 3x
dx = (1/3) du
(1/3) u e^u * (1/3) du
= (1/9) u e^u du
= (1/9) [ ue^u  e^u]
= (1/9) [ 3x e^(3x)  e^(3x) ]

Math  Damon, Sunday, May 1, 2011 at 11:13am
d/dx ( 2e^(2x) ) = 4 e^(2x) so yes

Math  Hannah, Sunday, May 1, 2011 at 11:36am
for number 2 how did you get 2e^2x?
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