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July 25, 2014

July 25, 2014

Posted by **Hannah** on Sunday, May 1, 2011 at 10:47am.

integral of xe^3x dx

2) evaluate integral form 1 to 0 of 4e^2x dx

I just need help finding the anitderivative. Would it be 2e^2x?

- Math -
**Damon**, Sunday, May 1, 2011 at 11:12amu = 3x

dx = (1/3) du

(1/3) u e^u * (1/3) du

= (1/9) u e^u du

= (1/9) [ ue^u - e^u]

= (1/9) [ 3x e^(3x) - e^(3x) ]

- Math -
**Damon**, Sunday, May 1, 2011 at 11:13amd/dx ( 2e^(2x) ) = 4 e^(2x) so yes

- Math -
**Hannah**, Sunday, May 1, 2011 at 11:36amfor number 2 how did you get 2e^2x?

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