Posted by hehe on Sunday, May 1, 2011 at 3:15am.
(a) x = 37.0 cos53.1 * t = 22.22 t
y = 37.0 sin53.1 t - (g/2) t^2
= 29.59 t - 4.90 t^2
Vx = 22.22
Vy = 29.59 - 9.8 t
angle to horizontal = arctan Vy/Vx
Plug in t = 2 s
(b) Compute y at time when Vy = 0
t = Vyo/g = 3.02 s
y = (Vyo)^2/(2g)
(c) R = 2 Vo^2 sin53.1*cos53.1/g
= 0.96 Vo^2/g
Vo is the launch velocity and Vyo is the y component of the launch velocity
qweqwe
ere
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