Posted by **kozy** on Sunday, May 1, 2011 at 1:41am.

Given the quadratic function f(x) = 16x2 – 64x + 64, find a value of x such that f(x) = 16.

- math-quadratic equations -
**MathMate**, Sunday, May 1, 2011 at 7:01am
f(x) = 16x2 – 64x + 64

for f(x)=16, write:

16=16x² - 64x +64

transpose 16 to the right, and factor out numeric factor 16:

16(x² -4x +3) = 0

Factor expression

16(x-3)(x-1)=0

This means that x=3 or x=1, either one of which satisfies the equation

f(x)=16.

Check by substituting x=3 or x=1 in f(x).

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