Posted by Anonymous on Saturday, April 30, 2011 at 11:54pm.
Find the exponential function of the form y=ax^b whose graph passes through the points (3, 1/27) and (0,1).
I don't know where to begin with this problem??

Advanced Algebra  typo?  MathMate, Sunday, May 1, 2011 at 7:10am
(0,1) means when x=0, y=1.
When x=0,
y = a*0^b = 0 except when b=0, when y is undefined.
So y cannot equal 1 when x=0.
Please check if there is a typo, for example: y=ab^x instead.
If this is the case, then
at (0,1),
1=ab^0=a*1=a
so y=b^x
at (3,1/27)
1/27 = b^(3)
27 = b^3;
3^3=b^3
b=3

Advanced Algebra  Anonymous, Sunday, May 1, 2011 at 10:37am
So what do i put as the answer? is 3 the esponential function then?

Advanced Algebra  MathMate, Sunday, May 1, 2011 at 11:35am
"Please check if there is a typo,..."
When you see what the question actually asks, then you can decide which way to go.
Especially in exams, you need to doublecheck what you've copied the question correctly before you start.

Advanced Algebra  Kenya, Sunday, May 1, 2011 at 12:25pm
Im sorry yes there was a typo, you correctly fixed it. the b should be an x so it should look like this.
y=ab^x

Advanced Algebra  MathMate, Sunday, May 1, 2011 at 1:39pm
So the second solution would be appropriate. BUT... do make sure you understand how the solution was obtained, promise?

Advanced Algebra  Anonymous, Sunday, May 1, 2011 at 2:12pm
I do! thank you so much!!

Advanced Algebra :)  MathMate, Sunday, May 1, 2011 at 2:54pm
You're welcome!
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