Questions LLC
Login
or
Sign Up
Ask a New Question
Math
Algebra
solve the eauation check for extraneous solutions.
log5 x=4
1 answer
log5(x)=4
That mean x=5^4=625
x=625
You can
ask a new question
or
answer this question
.
Related Questions
Use log5(2)=0.4307 and log5(3)=0.6826 to approximate the value of log5=54.
According to the example in my book I would divide
Solve the equation check for extraneous solutions
6/6-4x/=8x+4 I used/ / for the brackets posssible answers x=1 x=5/2 or x=2
Evaluate the expression for the given value of the variable. Show your work.
[-4b-8]+[-1-b^2]+2b^3;b=-2 Solve the equation. Check
Given that log5 3=0.683 and log5 7=1.209.without using calculator,evaluate
(a) log5 1.4 b)log7 75 c) log3 125
if log5 4 = .8614 and log5 9 = 1.3652 find the approximate value of log5 36.
would I multiply .8614 and 1.3652 or add them?
Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.
Solve the equation.
Enter your answer and show all the steps that you use to solve this problem in the space provided. No credit will be given if no
Note: Enter your answer and show all the steps that you use to solve this problem in the space provided. No credit will be given
Solve for x: log5(x-2)+ log5 (x-4) = log6(x-1)
exponentiating to solve equations: solve the eaquation, cheack for extraneous solutions
log5(x+4)+log5(x+1)=2