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August 20, 2014

August 20, 2014

Posted by **Anonymous** on Saturday, April 30, 2011 at 9:27pm.

Answer: 299.8 m

I confused, i tried using sine law

these were my calculations but some how i'm not getting the right answer

sin54/270=sin 109/x

- Math grade 11 -
**Henry**, Sunday, May 1, 2011 at 9:56pm1st we draw a picture of the prob.

1. Draw a ver and hor line to form a rt

angle.

2. Draw the hyp. from top of ver line to the end of hor line.

The angle between the hyp and hor line = 54 deg.

3. Draw a 2nd hyp from the top of ver

line to a point on the hor line.The

distance from this point to bottom of

the ver line is 270m. The angle formed

is 71 deg. The dist. between the 2 points where the 2 hyp cross the hor

line is X.

tan54 = h / (270+X),

h = (270 + X)tan54,

tan71 = h / 270,

h = 270tan71,

h = (270 + X)tan54 = 270tan71,

Divide both sides by tan54:

270 + X = 270tan71 / tan54 = 569.71,

X = 569.71 - 270 = 299.7m.

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