Posted by ashley -- on Saturday, April 30, 2011 at 6:22pm.
f = 10 c,
!/Do + !/Di = 1/f
Di is the object distance.
1/40 + 1/Di = 1/f
1/Di = 1/f - 1/Di = 1/10 - 1/40 = 3/40
Di = ___ cm
The object height (4 cm) does not matter when location image location.
1/f=1/v+1/u
where f=focal length
v=image distance
u=object distance
1/10=1/v+1/40
1/10-1/40=3/40
3/40=1/v cross multiply
3v/3=40/3 divide both sides by 3
v=13.3 cm
suppose you place a 5.0cm tall spring in front of a concave mirror. the mirror has a focal length of 24cm. the spring forms an image that appears to be at the same position as the spring,but the image is inverted. where did you place the spring? how tall is the springs image?
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