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September 1, 2014

Homework Help: Math(Please check)

Posted by Hannah on Saturday, April 30, 2011 at 6:06pm.

evaluate the integral

integral of 3 to 2 x/(x^2-2)^2 dx

u=x^2-2

du=2x dx
1/2 du = x dx

integral of 1/u^2 du
-1/(x^2-2) Then I plug in 3 and 2 and subtract them form each other

-1/(3^2-2) - (-1/(2^2-2) Is this correct?

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