Posted by Hannah on Saturday, April 30, 2011 at 6:06pm.
evaluate the integral
integral of 3 to 2 x/(x^22)^2 dx
u=x^22
du=2x dx
1/2 du = x dx
integral of 1/u^2 du
1/(x^22) Then I plug in 3 and 2 and subtract them form each other
1/(3^22)  (1/(2^22) Is this correct?

Math(Please check)  MathMate, Saturday, April 30, 2011 at 9:09pm
The (1/2) has been missed out, should read:
∫ du/(2u^2)
=1/(2(x^22))
After that you can plug in the limits of integration. I get 5/28 integrating from 2 to 3.
The bottom limit is the start value, and the top value is the end value.
It is usual to go from 2 to 3, and rarely from 3 to 2. Please check.
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