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Posted by **Hannah** on Saturday, April 30, 2011 at 5:58pm.

integral of 8x cuberoot srqt(4x^2-9) dx

let u= 4x^2-9

du= 8x dx

I do not know what to do now

- Math(Please Clarify) -
**MathMate**, Saturday, April 30, 2011 at 8:52pmSo is it

"cuberoot" or "srqt" or both?

and is the 8x in the denominator, or is it "8 multiply..."?

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