Dilute H3PO4(aq) and NaOH(aq) are mixed in chemically equivalent quantities. Write the formula equation for the reaction
There are three chemically equivalent H ions; therefore, there are three neutralization reactions that can be written, one for each H as it is neutralized. Then there is a fourth equation that can be written for all three H ions being neutralized in one reaction.
H3PO4 + 3NaOH ==> Na3PO4 + 3H2O is for all being neutralized in one equation.
The formula equation for the reaction between dilute H3PO4(aq) and NaOH(aq) can be written as:
H3PO4(aq) + 3NaOH(aq) → Na3PO4(aq) + 3H2O(l)
To write the formula equation for the reaction between H3PO4(aq) and NaOH(aq), you need to understand the chemical formula for each compound and their respective reaction products.
First, let's determine the chemical formula for each compound:
- H3PO4 is phosphoric acid
- NaOH is sodium hydroxide
Now let's figure out the reaction between these two compounds:
- H3PO4 is an acid, and NaOH is a base. When an acid reacts with a base, they undergo a neutralization reaction.
- In a neutralization reaction, the acid's hydrogen ions (H+) react with the base's hydroxide ions (OH-) to form water (H2O).
- The remaining ions combine to form a salt. In this case, since NaOH is a strong base, the salt will be sodium phosphate (Na3PO4).
Based on this information, the formula equation for the reaction can be written as:
H3PO4(aq) + 3NaOH(aq) → 3H2O(l) + Na3PO4(aq)
In this equation, the subscript numbers indicate the stoichiometric coefficients, which represent the relative amounts of each compound in the reaction.