posted by Cheryl on .
The mass of calcium hydrogen carbonate that would be found in 52.0L of hard water in a bathtub is _______________ g.
The amount concentration of calcium hydrogen carbonate in the hard water is __________mmol/L
You don't provide enough information to solve this problem.
200 ppm Ca(HCO3)2 is 200 mg/L. In 52.0 L there will be 200 mg/L x 52.0 L = ?? mg. Convert that to grams.
200 ppm is 200 mg/L which is 0.200g/L. Convert 0.200 g Ca(HCO3)2 to moles (moles = grams/molar mass), then to mmoles.