How many grams of Li2SO4 are needed to prepare 250.0 mL of a 4.0% m/v Li2SO4 solution?

what is 250*.04 grams?

To find out how many grams of Li2SO4 are needed to prepare the solution, you need to use the following formula:

Mass (grams) = Volume (mL) × Concentration (g/mL)

In this case, the volume of the solution is given as 250.0 mL and the concentration is given as 4.0% m/v (mass/volume).

First, convert the concentration from a percentage to a decimal by dividing it by 100:

Concentration (decimal) = 4.0% / 100 = 0.04

Next, rearrange the formula to solve for mass:

Mass (grams) = Volume (mL) × Concentration (g/mL)

Mass (grams) = 250.0 mL × 0.04 g/mL

Now, multiply the volume by the concentration to get the mass:

Mass (grams) = 10 g

Therefore, you would need 10 grams of Li2SO4 to prepare 250.0 mL of a 4.0% m/v Li2SO4 solution.