Posted by **Hannah** on Saturday, April 30, 2011 at 11:00am.

1) h(t)=20(5/8) - 16(5/8)^2 + 10 = 65/4

All I need to know for this is how to calculate the fraction parts to get 65/4. I am not good with fractions.

2) A manufacturer's profit from producing x units of a product is given by P(x)=0.002x^3 - 0.01x^2 + 0.5x. At what production level(s) will the marginal profit be $9.30 per unit. Enter just an integer, no units.

the derivative would be p(x)=0.006x^2 - 0.02x + 0.50. Then would I just plug in 9.30 to x?

- Math(Please help) -
**PsyDAG**, Saturday, April 30, 2011 at 11:10am
1) (5/8)^2 = (5/8)(5/8) = 25/64

h(t) = 100/8 - 16 (25/64) + 10 =

800/64 - 400/64 + 640/64 = 1040/64 = 65/4

2) I would just plug the value in, but I don't know which equation you want to use.

- Math(Please help) -
**Hannah**, Saturday, April 30, 2011 at 11:30am
so 0.006(9.30)^2 - 0.02(9.30) + 0.50

- Math(Please help) -
**Hannah**, Saturday, April 30, 2011 at 11:34am
For the first question how did you get 800/64 and 640/64?

- Math(Please help) -
**bobpursley**, Saturday, April 30, 2011 at 11:40am
The 20*(5/8)^2= 20*25/64

The 640/64 came from 10= 10*64/64

## Answer This Question

## Related Questions

- College Algebra - A manufacturer of radios estimates that his daily cost of ...
- math - i m always having a problem in math. i can't do fraction easilly. im ...
- math - i need some to explain how to turn 1.05 into a fraction Do you know how ...
- math - i am having to add, subtract, multiplication and division on fractions. ...
- Math - A manufacturer estimates that the profit P from producing x units of a ...
- statistics - Assume that Acme Tires sells their high performance tires for $180 ...
- math - can someone show me how to solve this problem. It determines that in ...
- math - Will someone please show me how to do this problem. I have to write this ...
- High school - . A cement manufacturer has a cost of production of $28 for each ...
- multiplying fraction - what is 3/7 * 2/10= and 5/6*2/3= , 1/2*1/4=,4/5*3/5=,2/3*...

More Related Questions