Posted by Hannah on Friday, April 29, 2011 at 5:57pm.
df/dx = 2 e^y (3 x^2) = 6 x^2 e^y df/dy = 2 x^3 (de^y/dy) = 2 x^3 e^y (in other words partial with respect to y is original function)
for the first one how did you get (3x^2)?