isomers of c5h12 an be separated by fractional distillation. With suitable reason, state the oder in which they will distil.
Isomers of C5H12 can be separated by fractional distillation. The order in which these isomers will distil can be determined based on their boiling points, which are related to their molecular structures.
C5H12 is the chemical formula for pentane, which has three isomers: n-pentane, isopentane, and neopentane. Each of these isomers has a different arrangement of carbon atoms, resulting in different boiling points.
In the case of fractional distillation, the isomer with the lowest boiling point will vaporize first and therefore will distil first. The isomer with the highest boiling point will remain as a liquid and distil last.
The order in which the isomers of C5H12 will distil is as follows:
1. Isopentane (2-methylbutane): This isomer has a branching structure with a branched methyl group, resulting in weaker intermolecular forces. Isopentane has the lowest boiling point among the three isomers and will distil first.
2. n-Pentane (n-pentane): This isomer has a straight-chain structure with no branches. It has stronger intermolecular forces compared to isopentane due to the greater surface area for intermolecular interactions. Therefore, n-pentane will distil after isopentane, but before neopentane.
3. Neopentane (2,2-dimethylpropane): This isomer has a highly branched structure with two methyl groups attached to a central carbon atom. Neopentane has the highest boiling point among the three isomers due to the compact and symmetrical arrangement, which results in stronger intermolecular forces. Neopentane will distil last.
So, the order of distillation for the isomers of C5H12 is isopentane, n-pentane, and then neopentane.