Posted by Jen on Thursday, April 28, 2011 at 10:01pm.
the period of
y = (1/2)tan (3x + π/2) is π/3
the period of the other function is 2π/(1/3) = 6π
Related Questions
trig - Determine the period, amplitude and phase shift for each given function...
trig/math - Determine the period, amplitude and phase shift for each given ...
math - Determine the period, amplitude and phase shift for each given function: ...
solving trig. equations - tan(3x) + 1 = sec(3x) Thanks, pretend 3x equals x so ...
Math/Trig - Period: Asymptotes: Range: a) y= 2 sec (x) + 1 b) y= -2 csc (x - pi/...
trig 26 - simplify to a constant or trig func. 1. sec ²u-tan ²u/cos &...
Trig - Given: cos u = 3/5; 0 < u < pi/2 cos v = 5/13; 3pi/2 &...
math - Use the exact values of the sin, cos and tan of pi/3 and pi/6, and the ...
Trig. - sec^2xcotx-cotx=tanx (1/cos)^2 times (1/tan)-(1/tan)=tan (1/cos^2) times...
TRIG - I need to state the period and 2 consecutive asymptotes on the graph for ...
For Further Reading