Posted by **Robert** on Thursday, April 28, 2011 at 8:27pm.

Amy has $200 less invested at 9% than she does at 6.5%. If the annual return from the two investments is the same, how much is invested at each rate?

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**MathMate**, Thursday, April 28, 2011 at 9:06pm
If she invested $X at 9%, then she invested $(X+200) at 6.5%.

Since the return is the same, then

X*0.09 = (X+200)*0.065

X(0.09-0.065)=200*0.065

0.025X = 13

X = 13/0.025 = $520 at 9%

X+200 = $720 at 6.5%

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