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posted by Chris on Thursday, April 28, 2011 at 5:45pm.
Solve the exponential equation algebraically: 2^x+1=5^2x
2^(x+1) = 5^2x. Take log of both sides: (x+1)log2 = 2xlog5, 0.301X + 0.301 = 1.398X, 0.301X - 1.398X = -0.301, -1.097X = -0.301, X = 0.2744.
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