Posted by **Chris** on Thursday, April 28, 2011 at 5:45pm.

Solve the exponential equation algebraically:

2^x+1=5^2x

- College Algebra -
**Henry**, Saturday, April 30, 2011 at 4:00pm
2^(x+1) = 5^2x.

Take log of both sides:

(x+1)log2 = 2xlog5,

0.301X + 0.301 = 1.398X,

0.301X - 1.398X = -0.301,

-1.097X = -0.301,

X = 0.2744.

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