If 25 ml of bromine, a liquid element at room temperature, is added to 100ml of water, what would be the resulting molar concentration of bromine?

Please Help me!!!

To determine the molar concentration of bromine in the resulting solution, you need to calculate the number of moles of bromine and then divide it by the volume of the solution. Here's how you can do it step by step:

Step 1: Determine the number of moles of bromine.
To find the number of moles, you need to know the molar mass of bromine. The molar mass of bromine is 79.9 g/mol.

First, convert the given volume of bromine from milliliters to liters:
25 ml = 0.025 L (since there are 1000 milliliters in a liter)

To calculate the number of moles, use the formula:
moles = mass / molar mass

Mass of bromine = volume of bromine x density of bromine
Density of bromine = 3.10 g/ml (at room temperature)

Mass of bromine = 0.025 L x 3.10 g/ml = 0.0775 g

Moles of bromine = 0.0775 g / 79.9 g/mol ≈ 0.00097 mol (rounded to 4 decimal places)

Step 2: Determine the volume of the resulting solution.
The resulting solution is the sum of bromine and water volumes:

Total volume = volume of bromine + volume of water
Total volume = 0.025 L + 0.100 L = 0.125 L

Step 3: Calculate the molar concentration.
Molarity (molar concentration) is defined as moles of solute per liter of solution.

Molar concentration of bromine = Moles of bromine / Volume of solution
Molar concentration of bromine = 0.00097 mol / 0.125 L ≈ 0.0078 mol/L (rounded to 4 decimal places)

So, the resulting molar concentration of bromine in the solution would be approximately 0.0078 mol/L.