how many grams of glucose C6H12O6 would you need to make 250 mL of 1.0 M solution?
To determine the number of grams of glucose needed to make a 1.0 M solution in 250 mL, we can use the concept of molarity and the molecular formula of glucose (C6H12O6).
Here's how to calculate it:
1. Start by converting the volume from milliliters to liters. Since 1 L = 1000 mL, divide 250 mL by 1000 to get the volume in liters:
250 mL ÷ 1000 = 0.25 L
2. Next, use the formula of molarity (M) to find the number of moles of glucose needed. Molarity is defined as moles of solute per liter of solution. Rearrange the formula to solve for moles (n):
Molarity (M) = moles (n) / Volume (L)
Rearranging the formula gives:
Moles (n) = Molarity (M) * Volume (L)
Substituting the given values:
Moles (n) = 1.0 M * 0.25 L
Moles (n) = 0.25 moles
3. Finally, calculate the mass of glucose using its molar mass. The molar mass of glucose (C6H12O6) can be found by adding up the atomic masses of carbon, hydrogen, and oxygen.
C: 6 * 12.01 = 72.06 g/mol
H: 12 * 1.008 = 12.096 g/mol
O: 6 * 16.00 = 96.00 g/mol
Add the individual molar masses together:
Molar mass of glucose (C6H12O6) = 72.06 + 12.096 + 96.00 = 180.156 g/mol
Now multiply the number of moles of glucose by its molar mass to find the mass in grams:
Mass (g) = Moles (n) * Molar mass (g/mol)
Mass (g) = 0.25 moles * 180.156 g/mol
Mass (g) = 45.04 grams
Therefore, you would need approximately 45.04 grams of glucose (C6H12O6) to make a 1.0 M solution in 250 mL.